Answer
$60$
Work Step by Step
$\sum ^{5}_{i=1}\left( 5i-3\right) =\sum ^{5}_{i=1}5i-\sum ^{5}_{i=1}3=\dfrac {5\times n\times \left( n+1\right) }{2}-3n=\dfrac {5\times 5\times 6}{2}-3\times 5=60$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Review Exercises - Page 312: 19
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