Answer
$1275$
Work Step by Step
$\sum ^{30}_{i=1}\left( 3i-4\right) -\sum ^{30}_{i=1}3i-\sum ^{30}_{i=1}4=3\sum ^{30}_{i=1}i-\sum ^{30}_{i=1}4=3\times \dfrac {n\left( n+1\right) }{2}-4n=3\times \dfrac {30\times \left( 30+1\right) }{2}-4\times 30=1275$
