Answer
$\frac{1}{3(1)}+\frac{1}{3(2)}+\frac{1}{3(3)}...+\frac{1}{3(10)}$=$\frac{1}{3}\Sigma^{10}_{r=1}\frac{1}{r}$
Work Step by Step
$\frac{1}{3(1)}+\frac{1}{3(2)}+\frac{1}{3(3)}...+\frac{1}{3(10)}$=$\frac{1}{3}(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}...+\frac{1}{10})$
=$\frac{1}{3}\Sigma^{10}_{r=1}\frac{1}{r}$
