Answer
= $9x^{\frac{2}{3}}$ + $c$
Work Step by Step
$\int$ $\frac{6}{\sqrt[3] x}$ $dx$ = $\int$ $6x^{\frac{-1}{3}}$ $dx$
= $6x^{\frac{2}{3}}(\frac{3}{2})$ + $c$
= $9x^{\frac{2}{3}}$ + $c$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Review Exercises - Page 312: 4
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