Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 39



Work Step by Step

$f''(x)=2\hspace{8mm}f'(2)=5\hspace{8mm}f(2)=10$ $\int f''(x)dx=\int 2dx=2x+C=f'(x)$ $f'(2)=4+C=5$ $C=1$ $f'(x)=2x+1$ $\int f'(x)dx=\int (2x+1)dx=x^2+x+C=f(x)$ $f(2)=2^2+2+C=10$ $10-2-2^2=4$ $f(x)=x^2+x+4$
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