Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises: 28

Answer

$\frac{\theta^3}{3}+\tan{\theta}+C$

Work Step by Step

$\int(\theta^2+\sec^2{\theta})d\theta=\int\theta^2d\theta+\int\sec^2{\theta}d\theta$ $=\frac{\theta^3}{3}+\tan{\theta}+C$
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