Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 38



Work Step by Step

$f'(s)=10s-12s^3\hspace{10mm}f(3)=2$ $\int f'(s)ds=\int(10s-12s^3)ds=5s^2-3s^4+C=f(s)$ $f(3)=5\times9-3\times81+C=-198+C=2$ $C=200$ $f(s)=5s^2-3s^4+200$
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