Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises: 38

Answer

$f(s)=5s^2-3s^4+200$

Work Step by Step

$f'(s)=10s-12s^3\hspace{10mm}f(3)=2$ $\int f'(s)ds=\int(10s-12s^3)ds=5s^2-3s^4+C=f(s)$ $f(3)=5\times9-3\times81+C=-198+C=2$ $C=200$ $f(s)=5s^2-3s^4+200$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.