Answer
$2x^2+\cot{x}+C$
Work Step by Step
$\int(4x-\csc^2{x})dx=\int4xdx+\int(-\csc^2{x})dx=2x^2+\cot{x}+C$
CHECK:
$\frac{d}{dx}2x^2+\frac{d}{dx}\cot{x}+\frac{d}{dx}C=4x+-\csc^2{x}+0=4x-\csc^2{x}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.1 Exercises - Page 251: 32
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