Answer
$ y $ = $ 3t^{3} + C $
Work Step by Step
$\frac{dy}{dt} $ = $ 9t^{2}$
To get original equation, we have to integrate the aforementioned differential equation.
$y=\int dy=\int9t^{2} dt$
= $\frac{9t^{2+1}}{3} + C $
= $ 3t^{3} + C $
Hence, $ y $ = $ 3t^{3} + C $
