Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 27

Answer

$t+csc(t)+C$

Work Step by Step

Given: $\int(1-csc(t) cot(t))dt$ Integrate: Integral of $1$ is $t$ Integral of $-csc(t)cot(t)$ is $csc(t)+C$ So $\int(1-csc(t) cot(t))dt=t+csc(t)+C$ Check the result by differentiation: $\frac{d}{dt}(t+csc(t)+C)=1-csc(t)cot(t)$
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