Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 251: 18


$\int (\sqrt[4]{x^3}+1)dx=\dfrac{4}{7\sqrt[4]{x}}+x+C.$

Work Step by Step

$\int (\sqrt[4]{x^3}+1)dx=\int x^{\frac{3}{4}}dx+\int1 dx=\dfrac{4}{7\sqrt[4]{x}}+x+C.$ By differentiating, we get the same integrand we started with.
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