Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises: 29

Answer

$\tan{\theta}+\cos{\theta}+C$

Work Step by Step

$\int(\sec^2{\theta}-\sin{\theta})d\theta=\int\sec^2{\theta}d\theta+\int(-\sin\theta)d\theta$ $=\tan{\theta}+\cos{\theta}+C$ CHECK: $\frac{d}{d\theta}(\tan{\theta}+\cos{\theta}+C)$ $\frac{d}{d\theta}\tan{\theta}+\frac{d}{d\theta}\cos{\theta}+\frac{d}{d\theta}C=\sec^2{\theta}+-\sin{\theta}+0=\sec^2{\theta}-\sin{\theta}$
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