Answer
$= -\frac{1}{2x^{6}} + C$
Work Step by Step
$\int (\frac{3}{x^{7}})dx$
$\int (3x^{-7}) dx$
$= \frac{3x^{-6}}{-6} + C$
$= \frac{(3)(\frac{1}{x^{6}})}{-6}+C$
$= \frac{\frac{3}{x^{6}}}{-6}+C$
$= \frac{3}{x^{6}} \times \frac{1}{-6}+ C$
$= - \frac{3}{6x^{6}} + C$
$= -\frac{1}{2x^{6}} + C$
