Answer
$h(t)=2t^4+5t-11$
Work Step by Step
$h'(t)=8t^3+5\hspace{10mm}h(1)=-4$
$\int h'(t)dt=\int (8t^3+5)dt=2t^4+5t+C=h(t)$
$h(1)=2+5+C=7+C=-4$
$C=-11$
$h(t)=2t^4+5t-11$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.1 Exercises - Page 251: 37
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