Answer
Converges to 0
Work Step by Step
The general term is $T_{n}=\frac{(-1)^{n+1}}{3^{n+4}}$
$\lim\limits_{n \to \infty}$ $T_{n}$ = $\lim\limits_{n \to \infty}$ $\frac{(-1)^{n+1}}{3n+4}$ = $\frac{(-1)^{n+1}}{\infty}$ = 0
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 9 - Infinite Series - 9.1 Sequences - Exercises Set 9.1 - Page 606: 30
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
