Answer
General term:$$\frac{3}{2^{n-1}}$$
Sequence converges to $0$.
Work Step by Step
The sequence can be written as $\frac{3}{2^0}, \frac{3}{2^1}, \frac{3}{2^2}, \frac{3}{2^3}, ...$. Here, the only changing part is the exponent of the denominator. Since, the general term starts with $n=1$, we need to have the exponent $0$ when $n=1$. This is possible when exponent is expressed as $n-1$. Thus, the general term is $$\frac{3}{2^{n-1}}$$
As $n\to\infty$, the denominator term increases and also tends to $\infty$, whereas the numerator term remains constant. Thus, $$\lim_{n\to\infty}{\frac{3}{2^{n-1}}}=0.$$
Thus, the sequence converges to $0$.
