Answer
General term:
$$(-1)^{n}n$$
This sequence does not converges.
Work Step by Step
Each term of the sequence is $n$ with alternating sign. This suggests that $(-1)^n$ term is multiplied with each term of the sequence. Thus, general term: $$(-1)^{n}n$$
As $n\to\infty$, the general term keep on increasing in magnitude, thus the limit doesn't exist. Thus, the sequence does not converges.
