Answer
$0$
Work Step by Step
$\lim_{n \to \infty} a_n = \lim_{n \to \infty}\frac{(-1)^{n+1}}{3^n}=\frac{(-1)^{n+1}}{\infty}=0$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 9 - Infinite Series - 9.1 Sequences - Exercises Set 9.1 - Page 606: 25
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