Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.1 Sequences - Exercises Set 9.1 - Page 606: 24

Answer

$0$

Work Step by Step

$\lim_{n \to \infty} a_n = \lim_{n \to \infty}\frac{n-1}{n^2}=\lim_{n \to \infty}\frac{n}{n^2}-\frac{1}{n^2}=\lim_{n \to \infty}\frac{1}{n}-\frac{1}{n^2}=0-0=0$
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