Answer
$$-\frac{506}{15}$$
Work Step by Step
Rewrite integral
$\int_{9}^{4}(-u+4) \sqrt{u} d u$
$-x+4=u$ and $-d x=d u$
$\int_{4}^{9}(-4+u) \sqrt{u} d u$
Expand brackets
\[
\int_{9}^{4} -4 u^{1 / 2}+ u^{3 / 2} d u
\]
$$-\frac{506}{15}$$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - Chapter 4 Review Exercises - Page 345: 74
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