Answer
Distance: $20 \mathrm{m}$
Displacement: 12 $\mathrm{m}$
Work Step by Step
Displacement is an integral of the velocity evaluated over the given interval.
\[
\text { Displacement }=\int_{0}^{6}(-4+2 t) d t=12 \mathrm{m}
\]
The distance traveled is the integral of the absolute value of the velocity evaluated over the given interval.
\[
\begin{array}{l}
\text { Distance }=\int_{0}^{6}|-4+2 t| d t \\
=-\int_{0}^{2}(-4+2 t) d t+\int_{2}^{6}(-4+2 t) d t \\
=20 \mathrm{m}
\end{array}
\]
