Answer
Distance: $6 \mathrm{m}$
Displacement: $6 \mathrm{m}$
Work Step by Step
The displacement is an integral of the absolute value of the velocity that was evaluated over the given interval.
\[
\begin{array}{l}
\text { Distance }=\int_{4}^{9}\left|\frac{3}{\sqrt{t}}\right| d t \\
=\int_{4}^{9}\left(\frac{3}{\sqrt{t}}\right) d t \\
=6 \mathrm{m}
\end{array}
\]
Displacement is an integral of the velocity that was evaluated over the given interval.
\[
\text { Displacement }=\int_{4}^{9}\left(\frac{3}{\sqrt{t}}\right) d t=6 \mathrm{m}
\]
