Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.9 Evaluating Definite Integrals By Substitution - Exercises Set 4.9 - Page 340: 17

Answer

$$\frac{2}{\pi }{\text{m}}$$

Work Step by Step

$$\eqalign{ & {\text{The distance traveled is given by }} \cr & s = \int_0^1 {\sin \pi t} dt \cr & {\text{Integrate and evaluate}} \cr & s = - \frac{1}{\pi }\left[ {\cos \pi t} \right]_0^1{\text{m}} \cr & s = - \frac{1}{\pi }\left[ {\cos \pi \left( 1 \right) - \cos \pi \left( 0 \right)} \right]{\text{m}} \cr & {\text{Simplify}} \cr & s = - \frac{1}{\pi }\left[ {\cos \pi - \cos 0} \right]{\text{m}} \cr & s = \frac{2}{\pi }{\text{m}} \cr} $$
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