Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 5 - Section 5.5 - The Substitution Rule - 5.5 Exercises - Page 426: 56

Answer

$\frac{1}{3}\tan^3\theta$

Work Step by Step

Let $u=\tan\theta$. then $du=\sec^2\theta \ d\theta$. Now we can re-write the integral as $$\int u^2 \ du = \frac{1}{3}u^3=\frac{1}{3}\tan ^3\theta$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.