Answer
$$\int\frac{\cos(\ln t)}{t}dt=\sin(\ln t)+C$$
Work Step by Step
$$A=\int\frac{\cos(\ln t)}{t}dt$$
Let $u=\ln t$
Then we have $du=\frac{1}{t}dt$.
Substitute into $A$: $$A=\int\cos udu$$ $$A=\sin u+C$$ $$A=\sin(\ln t)+C$$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 5 - Section 5.5 - The Substitution Rule - 5.5 Exercises - Page 426: 48
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