Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Test - Page 659: 4

Answer

Constant $=\frac{1}{25}$. Perfect square trinomial $=x^2+\frac{2}{5}x+\frac{1}{25}$. Factor form $=(x+\frac{1}{5})^2$.

Work Step by Step

The given expression is in the form of $x^2+bx$ where $b=\frac{2}{5}$. Add $\left (\frac{b}{2} \right )^2$ to complete the square. Therefore we add $=\left (\frac{b}{2} \right )^2$ $=\left (\frac{2}{2\cdot5} \right )^2$ $=\left (\frac{1}{5} \right )^2$ $=\frac{1}{25}$ Hence, the perfect square trinomial is $=x^2+\frac{2}{5}x+\frac{1}{25}$ Perfect square in the factor form is $=\left (x+\frac{b}{2} \right )^2$ $=(x+\frac{1}{5})^2$.
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