Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Test - Page 659: 11

Answer

$\{-2\pm5i\}$.

Work Step by Step

Subtract $25$ from both sides of the given equation. $\Rightarrow (x+2)^2+25-25=0-25$ Simplify. $\Rightarrow (x+2)^2=-25$ Apply the Square Root Property. $\Rightarrow x+2=+\sqrt{-25}$ or $x+2=-\sqrt{-25}$ Sinplify. $\Rightarrow x+2=+\sqrt{5^2}\sqrt{-1}$ or $x+2=-\sqrt{5^2}\sqrt{-1}$ Use $\sqrt{-1}=i$ $\Rightarrow x+2=+5i$ or $x+2=-5i$ Subtract $2$ from both sides. $\Rightarrow x+2-2=+5i-2$ or $x+2-2=-5i-2$ Simplify. $\Rightarrow x=-2+5i$ or $x=-2-5i$ Or we can write. $\Rightarrow x=-2\pm5i$. The solution set is $\{-2\pm5i\}$.
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