Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 338: 108

Answer

$81x^4-256$

Work Step by Step

The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$. Hence here: $(3x+4)(3x-4)(9x^2+16)=((3x)^2-4^2)(9x^2+16)=(9x^2-16)(9x^2+16)=(9x^2)^2-16^2=81x^4-256$
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