Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 338: 105

Answer

$-9x^2+3x+9$.

Work Step by Step

The given expression is $=(5x-7)(3x-2)-(4x-5)(6x-1)$ In each operation multiply the second bracket by each term of the first bracket as shown below. $=5x(3x-2)-7(3x-2)-[4x(6x-1)-5(6x-1)]$ Clear the parentheses. $=15x^2-10x-21x+14-[24x^2-4x-30x+5]$ Simplify. $=15x^2-31x+14-[24x^2-34x+5]$ $=15x^2-31x+14-24x^2+34x-5$ $=-9x^2+3x+9$.
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