Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 338: 101

Answer

(a.) $f(a+2)=3a^2+14a+15$. (b.) $f(a+h)-f(a)=6ah+3h^2+2h$.

Work Step by Step

The given function is $f(x)=3x^2+2x-1$ (a.) Plug $x=a+2$ into the given function. $f(a+2)=3(a+2)^2+2(a+2)-1$ Clear the parentheses. $f(a+2)=3a^2+12a+12+2a+4-1$ Simplify. $f(a+2)=3a^2+14a+15$. (b.) Plug $x=a+h$ into the given function. $f(a+h)=3(a+h)^2+2(a+h)-1$ Clear the parentheses. $f(a+h)=3a^2+6ah+3h^2+2a+2h-1$... (1) Now plug $x=a$ into the given function. $f(a)=3(a)^2+2(a)-1$ Clear the parentheses. $f(a)=3a^2+2a-1$ ...(2) Subtract function (2) from function (1). $f(a+h)-f(a)=(3a^2+6ah+3h^2+2a+2h-1)-(3a^2+2a-1)$ Clear the parentheses. $f(a+h)-f(a)=3a^2+6ah+3h^2+2a+2h-1-3a^2-2a+1$ Simplify. $f(a+h)-f(a)=6ah+3h^2+2h$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.