Answer
$9x^2+12x+4-25y^2$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
The square of a binomial sum is: $(A+B)^2=A^2+2AB+B^2$.
The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $[(3x+2)+5y][(3x+2)-5y]=(3x+2)^2-(5y)^2=(3x)^2+2\cdot3x \cdot2+2^2-25y^2=9x^2+12x+4-25y^2$
