Answer
$4x^4+12x^2y+9y^2$
Work Step by Step
The square of a binomial sum is: $(A+B)^2=A^2+2AB+B^2$.
The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $(2x^2+3y)^2=(2x^2)^2+2\cdot2x^2\cdot3y+(3y)^2=4x^4+12x^2y+9y^2$
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