Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 338: 102

Answer

(a.) $f(a+2)=4a^2+21a+25$. (b.) $f(a+h)-f(a)=8ah+4h^2+5h$.

Work Step by Step

The given function is $f(x)=4x^2+5x-1$ (a.) Plug $x=a+2$ into the given function. $f(a+2)=4(a+2)^2+5(a+2)-1$ Clear the parentheses. $f(a+2)=4a^2+16a+16+5a+10-1$ Simplify. $f(a+2)=4a^2+21a+25$. (b.) Plug $x=a+h$ into the given function. $f(a+h)=4(a+h)^2+5(a+h)-1$ Clear the parentheses. $f(a+h)=4a^2+8ah+4h^2+5a+5h-1$... (1) Now plug $x=a$ into the given function. $f(a)=4(a)^2+5(a)-1$ Clear the parentheses. $f(a)=4a^2+5a-1$ ...(2) Subtract function (2) from function (1). $f(a+h)-f(a)=(4a^2+8ah+4h^2+5a+5h-1)-(4a^2+5a-1)$ Clear the parentheses. $f(a+h)-f(a)=4a^2+8ah+4h^2+5a+5h-1-4a^2-5a+1$ Simplify. $f(a+h)-f(a)=8ah+4h^2+5h$.
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