Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 338: 106

Answer

$-x^2-8x-47$.

Work Step by Step

The given expression is $=(3x+5)(2x-9)-(7x-2)(x-1)$ In each operation multiply the second bracket by each term of the first bracket as shown below. $=3x(2x-9)+5(2x-9)-[7x(x-1)-2(x-1)]$ Clear the parentheses. $=6x^2-27x+10x-45-[7x^2-7x-2x+2]$ Simplify. $=6x^2-17x-45-[7x^2-9x+2]$ $=6x^2-17x-45-7x^2+9x-2$ $=-x^2-8x-47$.
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