Answer
$49x^2y^4-100y^{2}$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence here: $(7xy^2-10y)(7xy^2+10y)=(7xy^2)^2-(10y)^2=49x^2y^4-100y^{2}$
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