Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 338: 79

Answer

$49x^2y^4-100y^{2}$

Work Step by Step

The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$. Hence here: $(7xy^2-10y)(7xy^2+10y)=(7xy^2)^2-(10y)^2=49x^2y^4-100y^{2}$
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