Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 339: 109

Answer

$(x-1)^3=x^3-3x^2+3x-1$.

Work Step by Step

The given expression is $(x-1)^3$ The formula for the cube of an algebraic expression is $(a-b)^3=a^3-b^3-3a^2b+3ab^2$ Plug $a=x$ and $b=1$ into the formula. $(x-1)^3=x^3-1^3-3(x)^2(1)+3(x)(1)^2$ Clear the parentheses. $(x-1)^3=x^3-1-3x^2+3x$ Simplify. $(x-1)^3=x^3-3x^2+3x-1$.
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