Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 339: 110

Answer

$(x-2)^3=x^3-6x^2+12x-8$.

Work Step by Step

The given expression is $(x-2)^3$ The formula for the cube of an algebraic expression is $(a-b)^3=a^3-b^3-3a^2b+3ab^2$ Plug $a=x$ and $b=2$ into the formula. $(x-2)^3=x^3-2^3-3(x)^2(2)+3(x)(2)^2$ Clear the parentheses. $(x-2)^3=x^3-8-6x^2+12x$ Simplify. $(x-2)^3=x^3-6x^2+12x-8$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.