Answer
$4x^2-28x+49$
Work Step by Step
The square of a binomial sum is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $\frac{(2x-7)^5}{(2x-7)^3}=(2x-7)^{5-3}=(2x-7)^2=(2x)^2-2\cdot2x\cdot7+7^2=4x^2-28x+49$
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