Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 50

Answer

The answer is The sixth month salary $=\$42,823$. The total salary for the six month $=\$223,210$.

Work Step by Step

Salary for the first year $P=\$32,000$. Rate of increase $r=6\%=0.06$. Increment $=1+.06=1.06$. Time t=6. The salary in the sixth year is $32,000(1.06)^5 = \$42,823.2184832$ Round to the nearest dollar $=\$42,823$. Total salary is $32,000+32,000(1.06)^1+32,000(1.06)^2+...+32,000(1.06)^5$ The above series is the geometric sequence therefore, the sum of the series is $=32,000\frac{(1-1.06^6)}{1−1.06}=223210.193203$ Round to the nearest dollar$=\$ 223210$.
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