Answer
$\dfrac{27}{2}$
Work Step by Step
Since, we have $S_{\infty}=\dfrac{a_1}{1-r}$
Here, $a_1=9,r=\dfrac{1}{3}$
Thus,
$S_{\infty}=\dfrac{9}{1-(\dfrac{1}{3})}=\dfrac{27}{2}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Review Exercises - Page 870: 43
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