Answer
$\dfrac{127}{8}$
Work Step by Step
Since, we have $S_n=\dfrac{a_1(1-r^{n})}{1-r}$
Here, $n=7,a_1=8,r=\dfrac{1}{2}$
Thus,
$S_{7}=\dfrac{8[1-(\dfrac{1}{2})^{7}]}{1-(\dfrac{1}{2})}=16[\dfrac{127}{128}]=\dfrac{127}{8}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Review Exercises - Page 870: 39
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