Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 28

Answer

$a_1=3$,$a_2=6$,$a_3=12$,$a_4=24$, $a_5=48$

Work Step by Step

Initial term, $a_1=3$ and common ratio $r=2$. Now, we need first five terms of a geometric sequence such as: $a_1=3$;$a_2=3(2)=6$;$a_3=6(2)=12$;$a_4=12(2)=24$; $a_5=24(2)=48$ Hence, five terms are: $a_1=3$,$a_2=6$,$a_3=12$,$a_4=24$, $a_5=48$
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