Answer
$\dfrac{-4}{729}$
Work Step by Step
Since, we have $a_n=a_1r^{n-1}$
Here, $n=8,a_1=12,r=\dfrac{-1}{3}$
Thus,
$a_8=(12)(\dfrac{-1}{3})^{8-1}=12(\dfrac{-1}{3})^7=\dfrac{-4}{729}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Review Exercises - Page 870: 37
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