Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 45



Work Step by Step

Since, we have $S_{\infty}=\dfrac{a_1}{1-r}$ Here, $a_1=-6,r=\dfrac{-2}{3}$ Thus, $S_{\infty}=\dfrac{-6}{1-(\dfrac{-2}{3})}=\dfrac{-18}{5}$
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