Answer
$\dfrac{-18}{5}$
Work Step by Step
Since, we have $S_{\infty}=\dfrac{a_1}{1-r}$
Here, $a_1=-6,r=\dfrac{-2}{3}$
Thus,
$S_{\infty}=\dfrac{-6}{1-(\dfrac{-2}{3})}=\dfrac{-18}{5}$
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