Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 34



Work Step by Step

Since, we have $a_n=a_1r^{n-1}$ Here, $n=5,a_1=-3,r=2$ Thus, $a_5=(-3)(2)^{5-1}=-3(2)^4=-48$
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