Answer
$a_1=\dfrac{1}{2}$,$a_2=\dfrac{1}{4}$,$a_3=\dfrac{1}{8}$,$a_4=\dfrac{1}{16}$,
$a_5=\dfrac{1}{32}$
Work Step by Step
Initial term, $a_1=\dfrac{1}{2}$ and common ratio $r=\dfrac{1}{2}$.
Now, we need first five terms of a geometric sequence such as:
$a_1=\dfrac{1}{2}$;$a_2=\dfrac{1}{2}(\dfrac{1}{2})=\dfrac{1}{4}$;$a_3=\dfrac{1}{4}(\dfrac{1}{2})=\dfrac{1}{8}$;$a_4=\dfrac{1}{8}(\dfrac{1}{2})=\dfrac{1}{16}$;
$a_5=\dfrac{1}{16}(\dfrac{1}{2})=\dfrac{1}{32}$
Hence, five terms are: $a_1=\dfrac{1}{2}$,$a_2=\dfrac{1}{4}$,$a_3=\dfrac{1}{8}$,$a_4=\dfrac{1}{16}$,
$a_5=\dfrac{1}{32}$