Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 29

Answer

$a_1=\dfrac{1}{2}$,$a_2=\dfrac{1}{4}$,$a_3=\dfrac{1}{8}$,$a_4=\dfrac{1}{16}$, $a_5=\dfrac{1}{32}$

Work Step by Step

Initial term, $a_1=\dfrac{1}{2}$ and common ratio $r=\dfrac{1}{2}$. Now, we need first five terms of a geometric sequence such as: $a_1=\dfrac{1}{2}$;$a_2=\dfrac{1}{2}(\dfrac{1}{2})=\dfrac{1}{4}$;$a_3=\dfrac{1}{4}(\dfrac{1}{2})=\dfrac{1}{8}$;$a_4=\dfrac{1}{8}(\dfrac{1}{2})=\dfrac{1}{16}$; $a_5=\dfrac{1}{16}(\dfrac{1}{2})=\dfrac{1}{32}$ Hence, five terms are: $a_1=\dfrac{1}{2}$,$a_2=\dfrac{1}{4}$,$a_3=\dfrac{1}{8}$,$a_4=\dfrac{1}{16}$, $a_5=\dfrac{1}{32}$
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