Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 40



Work Step by Step

Since, we have $S_n=\dfrac{a_1(1-r^{n})}{1-r}$ Here, $n=6,a_1=5,r=5$ Thus, $S_{6}=\dfrac{5[1-(5)^{6}]}{1-5}=\dfrac{5}{-4}(-15624)=19530$
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