Answer
$a_1=16$,$a_2=-4$;$a_3=1$,$a_4=\dfrac{-1}{4}$,
$a_5=\dfrac{1}{16}$
Work Step by Step
Initial term, $a_1=16$ and common ratio $r=\dfrac{-1}{4}$.
Now, we need first five terms of a geometric sequence such as:
$a_1=16$;$a_2=16(\dfrac{-1}{4})=-4$;$a_3=-4(\dfrac{-1}{4})=1$;$a_4=1(\dfrac{-1}{4})=\dfrac{-1}{4}$;
$a_5=\dfrac{-1}{4}(\dfrac{-1}{-4})=\dfrac{1}{16}$
Hence, five terms are: $a_1=16$;$a_2=-4$;$a_3=1$;$a_4=\dfrac{-1}{4}$;
$a_5=\dfrac{1}{16}$
