Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 870: 30


$a_1=16$,$a_2=-4$;$a_3=1$,$a_4=\dfrac{-1}{4}$, $a_5=\dfrac{1}{16}$

Work Step by Step

Initial term, $a_1=16$ and common ratio $r=\dfrac{-1}{4}$. Now, we need first five terms of a geometric sequence such as: $a_1=16$;$a_2=16(\dfrac{-1}{4})=-4$;$a_3=-4(\dfrac{-1}{4})=1$;$a_4=1(\dfrac{-1}{4})=\dfrac{-1}{4}$; $a_5=\dfrac{-1}{4}(\dfrac{-1}{-4})=\dfrac{1}{16}$ Hence, five terms are: $a_1=16$;$a_2=-4$;$a_3=1$;$a_4=\dfrac{-1}{4}$; $a_5=\dfrac{1}{16}$
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