Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.7 Graphing Quadratics from Standard Form - 4.7 Exercises - Page 385: 15

Answer

a) $\$2975$ b) Vertex: $(50,2875)$ c) No amount of uniforms can be made of a budget of $\$1600$

Work Step by Step

Given \begin{equation} C(u)=\frac{1}{4} u^2-25 u+3500. \end{equation} a) Set $u= 30$ to find the cost of producing $30$ uniforms. $$ \begin{aligned} C(30) & =\frac{1}{4} \cdot 30^2-25 \cdot 30+3500 \\ & =2975. \end{aligned} $$ b) To find the vertex of the cost function, we use $a= 1/4$ and $b= -25$ into the following formula. $$ \begin{aligned} & x=\frac{-b}{2 a}=\frac{-(-25)}{2(0.25)}=50 \\ & y=\frac{1}{4} \cdot 50^2-25\cdot 50+3500=2875. \end{aligned} $$ The vertex is $(50,2875)$. The means that the minimum cost of producing $50$ uniforms is about $\$2875$. c) Set $C(u)= 1600$ to find the values of $u$. $$ \begin{aligned} \frac{1}{4} u^2-25 u+3500&=1600\\ \left(\frac{1}{4} u^2-25 u+3500\right)\cdot 4&=1600\cdot 4 \\ u^2-100 u+14000&=6400 \\ u^2-100 u+14000-6400&= 0\\ u^2-100 u+7600&= 0\\ u& =\frac{-(-100) \pm \sqrt{100^2-4 \cdot 7600}}{2} \\ & =\frac{100 \pm \sqrt{-20400}}{2}. \end{aligned} $$ This result shows that it is impossible to produce any number of uniform with a budget of $\$1600$.
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