Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.4 Solving Quadratic Equations by the Square Root Property and Completing the Square - 4.4 Exercises - Page 349: 78

Answer

See graph

Work Step by Step

The function that we want to graph is shown below. Follow the steps outline to graph the function.$$ f(x)=-2(x+6)^2+20. $$ Step 1: We first determine the direction in which the function opens: The given function opens upward because the constant $a= -2$ is negative. Step 2: Determine the vertex and the equation for the axis of symmetry. The vertex is $(-6,20)$ and the equation for the axis of symmetry is $x = -6$. Step 3: Find the $y$ and $x$ intercepts. To find the $y$ intercept, set $x= 0$ to find the value of $y$. Similarly, to find the $x$ intercept, set $ y= 0$ to find the values of $x$. $$ \begin{aligned} f(0) & =-2(0+6)^2+20 \\ & =-2(36)+20 \\ & =-52. \end{aligned} $$ $y$-intercept: $(0,-52)$. Set $ y = 0$ and solve. $$ \begin{aligned} -2(x+6)^2+20 & =0 \\ -2(x+6)^2 & =-20 \\ (x+6)^2 & =\frac{-20}{-2} \\ (x+6)^2 & =10 \\ x+6 & = \pm \sqrt{10} \\ x & =-6 \pm \sqrt{10}. \end{aligned} $$ Find the two separate solutions: $$ \begin{aligned} x & =-6-\sqrt{10} \\ & =-9.16 \\ x & =-6+\sqrt{10} \\ & =-2.84 \end{aligned} $$ $x$-intercept: $(-9.16,0), (-2.84, 0)$. Step 4: Find the domain and range of the function and sketch it. Domain: All real numbers, Range: $(-\infty, 20] $.
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